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第2章 习题参考答案

茆诗松、程依明、濮晓龙编著高等教育出版社《概率论与数理统计教程(第三版)》大学本科 · 教材双语助读 (Alt+Y)
习题2.1 答案
1. (1) frac XP | l l l 3 & 4 & 5 0. 1 & 0. 3 & 0. 6 .; (2) F (x) = { l l 0, & x < 3, 0. 1, & 3 ≤slant x < 4, 0. 4, & 4 ≤slant x < 5, 1, & 5 ≤slant x. .2. (1) c c c c c c c X & 1 & 2 & 3 & 4 & 5 & 6 hline P & frac 1 13 6 & frac 93 6 & frac 73 6 & frac 53 6 & frac 33 6 & frac 13 6 ;c c c c c c c Y & 0 & 1 & 2 & 3 & 4 & 5 hline P & frac 31 8 & frac 51 8 & frac 41 8 & frac 31 8 & frac 21 8 & frac 11 8 . tag 23. (1) c c c c c X & 1 & 2 & 3 & 4 hline P & frac 71 0 & frac 73 0 & frac 71 2 0 & frac 11 2 0 ;c c c c c X & 1 & 2 & 3 & 4 hline P & frac 71 0 & frac 62 5 & frac 2 75 0 0 & frac 35 0 0 . tag 24. (1) c c c c c X & 0 & 1 & 2 & 3 hline P & frac 53 0 & frac 1 53 0 & frac 93 0 & frac 13 0 ; (2) frac 13.c c c c c c X & 0 & 1 & 2 & 3 & 4 hline P & 0. 4 8 2 3 & 0. 3 8 5 8 & 0. 1 1 5 7 & 0. 0 1 5 4 & 0. 0 0 0 8 ;6. P (X = k) = frac binom 3 9 5 - k binom 1 3 kbinom 5 2 5, k = 0, 1, 2, 3, 4, 5.
  1. (1) P(X = k) = fracC₉0⁵ - kC₁0^kC₁00⁵, k = 0,1,2,3,4,5; (2) 0.416 2.

  2. X/P 1/4 (1)/(12) 1/6 1/2 . 1/3, 1/2, 2/3, 3/4 . 9. ln 2, 1, ln 1.25.

  3. 1 - α -β 11. (1) F(x) = { ll0, & x < 2, (3)/(10), & 2≤slant x < 3, (7)/(10), & 3≤slant x < 4, 1, & 4≤slant x; .

  4. F(x) = { ll0, & x < - 1, (x²)/(2) +x + 1/2, & -1≤slant x < 0, -(x²)/(2) +x + 1/2, & 0≤slant x < 1, 1, & 1≤slant x. . 13.0.875.

  5. (1) A = 1/2 ; (2) (√(2))/(4) . 15. (1) A = 1 ; (2) 0.4; (3) p(x) = 2x , 0 < x < 1 .

  6. (1) c = 21 ; (2) F(x) = 0, & x < 0, 7x³ + 1/2x², & 0 ≤slant x < 0.5, 1, & 0.5 ≤slant x; (3) (17)/(54) ; (4) (103)/(108) .

  7. 46 千升. 18. 3√(4) . 19. 略.

  1. E(X) = -0.2, E(3X + 5) = 4.4 . 2. 1.9. 3. 1.201.
X012345
P0.051 10.255 40.397 30.238 40.054 20.003 6
  1. 乙组砝码. 6. 2/9 . 7. (1 - (1 - p)^a)/(p) . 8. 先回答问题 2. 9. 正确. 10. 0.1 + p .

      1. 0.2. 13. 7. 14. 1.
  2. a = 1/3, b = 2 . 16. (1) 11; (2) 100; (3) 20. 17. 5. 18. 3/4 . 19—21. 略.

      1. 0.217 3. 3. 9. 4. 1/3 5. 6.5. 6. 1.5. 7. 0.05.
  1. (√(π))/(2), 1 - (π)/(4) . 9—13. 略. 14. 8/9 .

  1. 0.972. 2. 0.993 3. 3. 0.784. 4. 0.000 127 9. 5. n = 6, p = 0.4 .

  2. (80)/(81) . 7. (1) 0.1905; (2) 0.1912. 8. 0.0902. 9. 略. 10. 0.889.

  3. (1) 0.1875; (2) 0.0156. 12. n/m . 13. 1.

  4. (9)/(64) . 15. 1.055 6. 16. p > 1/2 . 17. E(X³) = λ³ + 2λ² .

18—20. 略.

  1. (20)/(27) . 2. 3/4 . 3. 4/5 . 4. 4. 5. (602)/(3) . 6. (π(a² + b² + ab))/(12) . 7. 21.

  2. 0.152 3. 9.4. 10.33.64 元. 11.0.516 7. 12. 1-e⁻1 .

  3. k = (ln 2)/(λ) . 14. [1,3]. 15. -2, (1)/(√(2)); 0, 1/2; 0, (1)/(√(2)) . 16. 0.593 4.

  4. (1) μ = 70, σ = 14.81 ; (2) 0.94. 18. 0.045 6. 19. 0.841 3.

  5. (1) 0.5328; (2) 0.6977; (3) 3.

  6. (1) 0.9544; (2) 0.6304; (3) d ≤slant 0.154 .

  7. 0.869 8. 23. (1) 0.158 7; (2) 0.691 5; (3) 0.682 6. 24. 78.75.

  8. a = 55.56, b = 58.5, c = 61.5, d = 64.44. 26.一样大小. 27.0.95.

  9. 不变. 29. 24.3. 30. σ √((2)/(π)) . 31. 由上题即可得. 32. 0.594 0.

  10. 0.2639, 0.1818. 34. 0.4096.

1.Y0149Z01232.Y-11
P 1/5 (7)/(30) 1/5 (11)/(30) P 1/5 (7)/(30) 1/5 (11)/(30) P0.50.5
  1. Y/P|ccc - 1 & 1 1/3 & 2/3 . 4. 1 - X∼ U(0,1) .5. p(y) = (2)/(π√(1 - y²)),0 < y < 1.

  2. p(y) = (1)/(√(π y)) , 0 < y < (π)/(4). 7. p(y) = (1)/(2y), e² < y < e⁴.

  3. (1) p(y) = (1)/(4√(y)) , 0 < y < 4 ; (2) (1)/(√(2)) . 9. (1) 1/2 ; (2) p(y) = y, 0 < y < 1 .

  4. (1) p(y) = 0.5e⁻0.5y , y > 0 ; (2) p(y) = 1/3 , 1 < y < 4 ; (3) p(y) = 1/y , 1 < y < e ;

(4) p(y) = e⁻y, y > 0.

  1. (1) p(y) = (y²)/(18) , -3 < y < 3; (2) p(y) = (3(3 - y)²)/(2) , 2 < y < 4; (3) p(y) = 3(√(y))/(2) , 0 < y < 1.

  2. p(y) = (1)/(√(2π y)σ)e⁻(y)/(2σ²), y > 0.

  3. p(y) = (1)/(√(2π)yσ)exp {-((ln y - μ)²)/(2σ²)}, y > 0.

E (Y) = exp {μ + frac σ^ 22 }, operatornameVar (Y) = e ^ 2 μ + σ^ 2 (e ^ σ^ 2 - 1).
  1. (1) p(y) = √((2)/(π)) e⁻(y²)/(2), y > 0; (2) p(y) = (1)/(2√(π(y - 1))) e⁻(y - 1)/(4), y > 1.

  2. (1) p(y) = 1/2 e⁻(y - 1)/(2) , y > 1 ; (2) p(y) = (1)/(y²) , y > 1 ; (3) p(y) = (1)/(2√(y)) e⁻√(y) , y > 0 .

16—17. 略. 18. 0.977 2.

1. μ_ 1 = frac a + b2, μ_ 2 = frac a ^ 2 + a b + b ^ 23, μ_ 3 = frac a ^ 3 + a ^ 2 b + a b ^ 2 + b ^ 34, μ_ 4 = frac a ^ 4 + a ^ 3 b + a ^ 2 b ^ 2 + a b ^ 3 + b ^ 45;ν_ 1 = 0, ν_ 2 = frac (b - a) ^ 21 2, ν_ 3 = 0, ν_ 4 = frac (b - a) ^ 48 0; β_ s = 0, β_ k = - 1. 2.
  1. (√(3))/(3) . 3. (1) (a + b)/(2) , (2) μ ; (3) e^(μ) .
μ_ 1 = frac αλ, μ_ 2 = frac α (α + 1)λ^ 2, μ_ 3 = frac α (α + 1) (α + 2)λ^ 3; ν_ 1 = 0, ν_ 2 = frac αλ^ 2, ν_ 3 = frac 2 αλ^ 3.μ_ 1 = frac 1λ, μ_ 2 = frac 2λ^ 2, μ_ 3 = frac 6λ^ 3, μ_ 4 = frac 2 4λ^ 4; ν_ 1 = 0, ν_ 2 = frac 1λ^ 2, ν_ 3 = frac 2λ^ 3, ν_ 4 = frac 9λ^ 4; C _ v (X) = 1, β_ s = 2, β_ k = 6.
  1. x₀.1 = 6.16, x₀.9 = 13.84.

  2. xₚ = η [-ln (1 - p)]¹/m ;当 m = 1.5, η = 1000 时, x₀.1 = 223.08, x₀.5 = 783.22, x₀.8 = 1373.36.

  3. x₀.1 = 0.211, x₀.5 = 1.386, x₀.8 = 3.219. 9—10. 略.

  4. (1) exp {μ + σ uₚ} ; (2) 62; (3) 341. 12. μ = 9.799, σ = 1.527 . 13. 4099kg .

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